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Let PA=6Ohm AB=14ohm BQ=10ohm PA and AB are in series then, total resistance R =6+14=20ohm AND this resistance R is parallel to the resistances of 20 ohm then,they will give a Resistance(let it be X) of 1/X=1/20+1/20 X=20/2=10ohm and this resistance X is in series with the resistances of 10 Ohm then, the new resistance Y=10+10=20 Ohm Y is parallel to the resistances PQ Total resistance of the circuit Rt 1/Rt =1/20+1/20 Rt =20/2=10ohm hence total resistance =10 ohms let I be the current flowing through the resistances of 25 Ohm V=70v I=V/R I=70/25+10[ since the resistances are in series ] I=70/35 I=2 Amperes
Answers & Comments
AB=14ohm
BQ=10ohm
PA and AB are in series then,
total resistance R =6+14=20ohm
AND this resistance R is parallel to the resistances of 20 ohm then,they will give a Resistance(let it be X) of
1/X=1/20+1/20
X=20/2=10ohm
and this resistance X is in series with the resistances of 10 Ohm
then, the new resistance Y=10+10=20 Ohm
Y is parallel to the resistances PQ
Total resistance of the circuit Rt
1/Rt =1/20+1/20
Rt =20/2=10ohm
hence total resistance =10 ohms
let I be the current flowing through the resistances of 25 Ohm
V=70v
I=V/R
I=70/25+10[ since the resistances are in series ]
I=70/35
I=2 Amperes