THAT IS THE ANSWER
《==PABRAINLEST==》KAKASHI
SO THE ANSWER IS:
1.M=3/2
E=3
2.E=3
#.
m=
e=3
##
C=2
Answer:
#.Solution given:
e=3[having right angle triangle with 45° is a isosceles triangle and so the base side of isosceles triangle are equal]
By using Pythagoras law:
p²+b²=h²
3²+3²=h²
9+9=h²
h=
##.
In right angled triangle:
Tan 30=
C=Tan30*2
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Answers & Comments
THAT IS THE ANSWER
《==PABRAINLEST==》KAKASHI
SO THE ANSWER IS:
1.M=3/2
E=3
2.E=3
#.
m=![\bold{3\sqrt{2}} \bold{3\sqrt{2}}](https://tex.z-dn.net/?f=%5Cbold%7B3%5Csqrt%7B2%7D%7D)
e=3
##
C=2
Answer:
#.Solution given:
e=3[having right angle triangle with 45° is a isosceles triangle and so the base side of isosceles triangle are equal]
By using Pythagoras law:
p²+b²=h²
3²+3²=h²
9+9=h²
h=![\sqrt{18}=\bold{3\sqrt{2}} \sqrt{18}=\bold{3\sqrt{2}}](https://tex.z-dn.net/?f=%5Csqrt%7B18%7D%3D%5Cbold%7B3%5Csqrt%7B2%7D%7D)
##.
In right angled triangle:
Tan 30=![\frac{opposite} {hypotenuse}=\frac{C}{2\sqrt{3}} \frac{opposite} {hypotenuse}=\frac{C}{2\sqrt{3}}](https://tex.z-dn.net/?f=%5Cfrac%7Bopposite%7D%20%7Bhypotenuse%7D%3D%5Cfrac%7BC%7D%7B2%5Csqrt%7B3%7D%7D)
C=Tan30*2![\sqrt{3} \sqrt{3}](https://tex.z-dn.net/?f=%5Csqrt%7B3%7D)
C=2