11) distance between observe C and vertical cliff is 40m for observe A tan48=height of cliff from ground to A /40m height of cliff from ground to A =40tan48 m for observe B tan57 =height of cliff from A +distance between A and B/40m distance between A and B =40tan57-40tan48 =40 (tan57-tan48) m
12) let height of pole =h man's height=x tan28=(h-x)/9 h-x=9tan28 -----(1) tan13=x/9 x=9tan13 ------(2) hence from equation (1) and (2) h=9 (tan28+tan13)
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11) distance between observe C and vertical cliff is 40mfor observe A
tan48=height of cliff from ground to A /40m
height of cliff from ground to A =40tan48 m
for observe B
tan57 =height of cliff from A +distance between A and B/40m
distance between A and B =40tan57-40tan48
=40 (tan57-tan48) m
12) let height of pole =h
man's height=x
tan28=(h-x)/9
h-x=9tan28 -----(1)
tan13=x/9
x=9tan13 ------(2)
hence from equation (1) and (2)
h=9 (tan28+tan13)