Answer:
x=26
Step-by-step explanation:
We know that 12,13,15 form a Pythagorean triplet..
then x/2=13
Then , x =26
Thanks and keep going!
18
Let Divide [tex]x[/tex] in 2 Parts So We Have, [tex]\frac{x}{2}[/tex] and [tex]\frac{x}{2}[/tex],
Now,
By Using Pythagoras Theorem We Have,
[tex](Hypotenuse)^{2} =(Perpendicular)^{2}+(Base)^{2}[/tex]
[tex]\frac{x}{2} =Base\\12= Perpendicular\\15=Hypotenous\\[/tex]
Putting This Values So We Have ,
[tex](15)^2+=(12)^2+(\frac{x}{2} )^2\\225=144+(\frac{x}{2} )^2\\81=(\frac{x}{2} )^2\\\sqrt{81} =(\frac{x}{2} )\\9=\frac{x}{2} \\x=18[/tex]
Hence We Have [tex]x[/tex]=18.
Please Mark this Answer as Brilliant , Thank You !
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Answers & Comments
Answer:
x=26
Step-by-step explanation:
We know that 12,13,15 form a Pythagorean triplet..
then x/2=13
Then , x =26
Thanks and keep going!
Verified answer
Answer:
18
Step-by-step explanation:
Let Divide [tex]x[/tex] in 2 Parts So We Have, [tex]\frac{x}{2}[/tex] and [tex]\frac{x}{2}[/tex],
Now,
By Using Pythagoras Theorem We Have,
[tex](Hypotenuse)^{2} =(Perpendicular)^{2}+(Base)^{2}[/tex]
[tex]\frac{x}{2} =Base\\12= Perpendicular\\15=Hypotenous\\[/tex]
Putting This Values So We Have ,
[tex](15)^2+=(12)^2+(\frac{x}{2} )^2\\225=144+(\frac{x}{2} )^2\\81=(\frac{x}{2} )^2\\\sqrt{81} =(\frac{x}{2} )\\9=\frac{x}{2} \\x=18[/tex]
Hence We Have [tex]x[/tex]=18.
Please Mark this Answer as Brilliant , Thank You !