calculate the volume of HCL gas formed and chlorine gas required when 40ml of methane reacts completely with chlorine at STP.
CH4+2CL2-----» CH2CL2+ 2HCL
CH4+2CL2-----» CH2CL2+ 2HCL
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CH4 + 2Cl2 → CH2Cl2 +2 HClHere, we see that 1 mole of CH4 react with 2 Mole of Cl2 form 1 mole of C2H2 and 2mole HCl.
it means 1 mole of CH4 , forms 2 mole of HCl .
so, 1 volume of CH4 forms 2volume of HCl.
hence,
40 ml of CH4 forms 2 × 40ml HCl
hence, volume of HCl = 80 ml