Verified answer

SOLUTION:

Step 1: List the given values.

[tex]\begin{aligned} & P = \text{6.54 atm} \\ & n = \text{2.12 mol} \\ & T = 76^{\circ}\text{C} = \text{349.15 K} \end{aligned}[/tex]

Step 2: Calculate the volume of the gas using ideal gas equation.

[tex]\begin{aligned} V & = \frac{nRT}{P} \\ & = \frac{(\text{2.12 mol})\left(0.082057 \: \dfrac{\text{L}\cdot\text{atm}}{\text{mol}\cdot\text{K}}\right)(\text{349.15 K})}{\text{6.54 atm}} \\ & = \boxed{\text{9.29 L}} \end{aligned}[/tex]

Hence, the volume of NO gas is 9.29 L.

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Note: Kindly swipe the screen to the left to see the continuation of the answers on the right side.

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