calculate the pressure exerted by a brick of dimensions 0.2m ×0.3m×0.6m that weighs 20N when kept on its sides widest base and narrowest base ..
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Explanation:
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Verified answer
Answer:
111.11 Pa and 333.33 Pa respectively
Explanation:
Pressure is Force/Area
Widest base = maximum area = 0.3m x 0.6m = [tex]0.18m^{2}[/tex]
Narrowest base = minimum area = 0.2m x 0.3m = [tex]0.06m^2[/tex]
[tex]\frac{20}{0.18} = 111.11[/tex]Pa for the widest base
[tex]\frac{20}{0.06} = 333.33[/tex]Pa for the narrowest base