Answer:
5.076.
Explanation:
H
2
→2H
+
+2e
E
/H
=E
∘
−
0.0591
log
P
[H
]
=0.0−0.0591log
1
0.25=0.0591 pH
pH=
0.25
=4.23
(b) E
[H+ ] 2
=0.0−0.591log
[H + ]
0.3=0.0591 pH
0.3
=5.076.
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Answers & Comments
Answer:
5.076.
Explanation:
H
2
→2H
+
+2e
E
H
2
/H
+
=E
H
2
/H
+
∘
−
2
0.0591
log
P
H
2
[H
+
]
2
=0.0−0.0591log
1
[H
+
]
0.25=0.0591 pH
pH=
0.0591
0.25
=4.23
(b) E
H
2
/H
+
=E
H
2
/H
+
∘
−
2
0.0591
log
P
H
2
[H+ ] 2
=0.0−0.591log
1
[H + ]
0.3=0.0591 pH
pH=
0.0591
0.3
=5.076.