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SOLUTION:

Step 1: List the given values.

[tex]\begin{aligned} & M = 0.200 \: M = \text{0.200 mol/L} \\ & T = 25^{\circ}\text{C} = \text{298.15 K} \end{aligned}[/tex]

Step 2: Determine the van't Hoff factor (i).

Since NaCl is a strong electrolyte, one mole of it dissociates into one Na⁺ and one Cl⁻ ion. In this case, the van't Hoff factor is

i = 2

Step 3: Calculate the osmotic pressure of the solution.

[tex]\begin{aligned} \pi & = iMRT \\ & = (2)(\text{0.200 mol/L})\left(0.082057 \: \dfrac{\text{L}\cdot\text{atm}}{\text{mol}\cdot\text{K}}\right)(\text{298.15 K}) \\ & = \boxed{\text{9.79 atm}} \end{aligned}[/tex]

Hence, the osmotic pressure is 9.79 atm.

[tex]\\[/tex]

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