Explanation:
Molar mass of CO
2
= 44; Molar mass of CO = 28
No. of CO
present in 8.8g =
44
8.8
=0.2moles
0.2 moles of CO
contain = 0.2×(6.023×10
23
)=1.2×10
molecules
∴ no. of moles of oxygen atoms in CO
=
6.023×10
2×(1.2×10
)
=0.4
As the no of Oxygen atoms present in CO is same as that of oxygen atoms present in 8.8g of CO
0.4=
28
wt
=11.2gm
∴ the no. of Oxygen atoms in CO = 0.4moles in 11.2gm of C
Answer. =44g. =1.2* 10^22 molecules.
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Answers & Comments
Explanation:
Molar mass of CO
2
= 44; Molar mass of CO = 28
No. of CO
2
present in 8.8g =
44
8.8
=0.2moles
0.2 moles of CO
2
contain = 0.2×(6.023×10
23
)=1.2×10
23
molecules
∴ no. of moles of oxygen atoms in CO
2
=
6.023×10
23
2×(1.2×10
23
)
=0.4
As the no of Oxygen atoms present in CO is same as that of oxygen atoms present in 8.8g of CO
2
0.4=
28
wt
=11.2gm
∴ the no. of Oxygen atoms in CO = 0.4moles in 11.2gm of C
Explanation:
Answer. =44g. =1.2* 10^22 molecules.