calculate the number of Aluminium ions present in 0.051 gram Aluminium oxide hint the mass of an Ion is the same as that of an atom of the same element atomic mass of aluminium is equal to 27 u
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Answer:
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Explanation:
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Answer:
Molar mass of Al2O3=2× mass of O=2×27+3×16=102g
1 mole of Al2O3 contains 2 moles of Aluminium ions
So, 102 g of Al2O3 contains 2×6.022×10^23 Aluminium ions
Hence,0.051 g of Al2O3 will contain =2×6.022×10^23 ×0.051/102 Aluminium ions
=6.022×10^20 Aluminium ions