Answer:
Here given..
98 % of H2SO4 that means 98 g of H2SO4 is there in 100 g of aq. H2SO4 solution.
Mass of solute = 98 g
Mass of solvent = 2 g (as water is considered as universal solvent)
Molar mass of solute = 98 g
Molar mass of solvent = 18 g
No of moles of solute = 1 mole (no of moles = given mass / molar mass)
No of moles of solvent = 2/18 = 1/9 mole
x( of solute) = Moles of solute/(moles of solute + moles of solvent)
x (of solute) = 1/(1+(1/9)) = 0.9
x (of solvent) = 1 - 0.9 = 0.1
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Answer:
Here given..
98 % of H2SO4 that means 98 g of H2SO4 is there in 100 g of aq. H2SO4 solution.
Mass of solute = 98 g
Mass of solvent = 2 g (as water is considered as universal solvent)
Molar mass of solute = 98 g
Molar mass of solvent = 18 g
No of moles of solute = 1 mole (no of moles = given mass / molar mass)
No of moles of solvent = 2/18 = 1/9 mole
x( of solute) = Moles of solute/(moles of solute + moles of solvent)
x (of solute) = 1/(1+(1/9)) = 0.9
x (of solvent) = 1 - 0.9 = 0.1