The molality of a solution is defined as the number of moles of solute (benzene in this case) per kilogram of solvent (CCl4). To calculate it, we first need to find the number of moles of benzene. This can be done using its molar mass, which is 78.1 g/mol. Then, we divide the number of moles of benzene by the mass of the solvent in kilograms:
moles of benzene = 13.0 g / 78.1 g/mol = 0.166 mol
moles of benzene = 13.0 g / 78.1 g/mol = 0.166 molmass of solvent (CCl4) in kilograms = 17.0 g / 1000 g/kg = 0.017 kg
molality = moles of solute / mass of solvent (in kilograms) = 0.166 mol / 0.017 kg = 9.76 mol/kg
So the molality of the solution made with 13.0 g benzene in 17.0 g CCl4 is 9.76 mol/kg.
Answers & Comments
Explanation:
The molality of a solution is defined as the number of moles of solute (benzene in this case) per kilogram of solvent (CCl4). To calculate it, we first need to find the number of moles of benzene. This can be done using its molar mass, which is 78.1 g/mol. Then, we divide the number of moles of benzene by the mass of the solvent in kilograms:
moles of benzene = 13.0 g / 78.1 g/mol = 0.166 mol
moles of benzene = 13.0 g / 78.1 g/mol = 0.166 molmass of solvent (CCl4) in kilograms = 17.0 g / 1000 g/kg = 0.017 kg
molality = moles of solute / mass of solvent (in kilograms) = 0.166 mol / 0.017 kg = 9.76 mol/kg
So the molality of the solution made with 13.0 g benzene in 17.0 g CCl4 is 9.76 mol/kg.