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Calculate the mass of sodium acetate [CH

3

COONa] required to make 500 mL of 0.375 molar aqueous solution. Molar mass of sodium acetate is 82.0245 g mol

−1

.

Hard

Solution

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0.375M solution means 0.375 moles in 1 L of solution.

1000mL of solution contains 0.375 moles

1mL of solution⟶

1000

0.375

moles

500mL of solution⟶

1000

0.375

×500

⟶0.1875

No. of moles=

Molar Mass

Mass

0.1875mol=

82.0245 gmol

−1

Mass

∴ Mass of the compound = 15.37 g.

Verified answer

Explanation:

0.375 M aqueous solution of sodium acetate means that 1000 mL of a solution containing 0.375 moles of sodium acetate.

1 ml of solution = 0.3751000moles

∴No. of moles of sodium acetate in 500 mL = (0.375/1000)×500 = 0.375/2 = 0.1875

Number of moles=Mass given/ Molecular mass

The molar mass of sodium acetate = 82.0245g/mol

∴Mass of sodium acetate acquired = 0.1875×82.0245 g = 15.380g