Calculate the mass of ice needed to cool 150 g of water contained in a calorimeter of mass 50 g at 32° C such that the final temperature is 5°C.Specific heat capacity of calorimeter = 0.4 J g-1 °C, specific heat capacity of water = 4.2J g^ -1 C^ -1 latent heat capacity of ice = 330 J g¹.
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Answer:
By law of conservation of energy, Heat energy imparted by water=heat energy taken by ice and melted ice. Amount of ice required for this process is 48.46 gm.
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