Explanation:

Answer

Consider a point P located on the axial line of a short bar magnet of magnetic length 2l and strength M. Let us find B at a point P which is at a distance z from the centre of magnet. Magnetic flux density of P due to N-pole is

B1=4πμ0((z−l)2M) along NP

Similarly on S-Pole

B2=4πμ0(z+l)2M along SP

Net magnetic flux at P is

B=B1−B2=4πμ0[(z−l)2M−(z+l)2M]

=4πμ0[(z2−l2)24Mzl]

=4πμ0[(z2−l2)2M

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Answer:

For a bar magnet, magnetic induction at a point on its axis is given by the formula,

B=4πμ0(d2+l2)3/2M

Where l is the length of bar magnet and d is distance of point from the centre of bar magnet. Hence, here, l=0.1 m and l=0.053 m.

Putting in the formula, we get B=10−4 T.