Answer:
In triangles BAD, angle D = 90°
Therefore by Pythagoras theorem,
AD^2 + BD^2 = AB^2
6^2 +BD^2 = 10^2
36 + BD^2 = 100
BD^2 = 64
BD = 8....(taking square roots)
Similarly, in triangle BDC,
BC^2 = 15^2 + 8^2
BC^2 = 225+64
BC^2 = 289
BC = 17....(taking square roots)
Hope it helps you...
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Verified answer
Answer:
In triangles BAD, angle D = 90°
Therefore by Pythagoras theorem,
AD^2 + BD^2 = AB^2
6^2 +BD^2 = 10^2
36 + BD^2 = 100
BD^2 = 64
BD = 8....(taking square roots)
Similarly, in triangle BDC,
BC^2 = 15^2 + 8^2
BC^2 = 225+64
BC^2 = 289
BC = 17....(taking square roots)
Hope it helps you...