Answer: The ionization energy of will be 122.4 eV.
Explanation:
Ionization energy is defined as the energy that is released when a valence electron is ejected out from an isolated gaseous atom.
The formula used to calculate ionization energy follows:
where,
Z = atomic number = 3 (for lithium)
n = Energy level
Electronic configuration for ion will be:
The transition of ionization energy is from
Putting values in above equation, we get:
Hence, the ionization energy of will be 122.4 eV.
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Answers & Comments
Answer: The ionization energy of will be 122.4 eV.
Explanation:
Ionization energy is defined as the energy that is released when a valence electron is ejected out from an isolated gaseous atom.
The formula used to calculate ionization energy follows:
where,
Z = atomic number = 3 (for lithium)
n = Energy level
Electronic configuration for ion will be:
The transition of ionization energy is from
Putting values in above equation, we get:
Hence, the ionization energy of will be 122.4 eV.
the ionisation energy of an H atom is 13.6eV.what is the ionisation energy for li2+ ion?
where Z is atomic number and n is the shell number.
so IE li^2+=13.6×9=122.eV.