Answer:

Let AB be a chord of a circle with centre O and radius 13 cm. Draw OL⊥AB. Join OA.

Here, OL=5 cm,OA=13 cm.

In right triangle OLA,

OA  

2

=OL  

2

+AL  

2

13  

2

=5  

2

+AL  

2

AL  

2

=144

AL=12

Since the perpendicular from the centre to a chord bisects the chord. Therefore,

AB=2AL=2×12=24 cm

solution

Step-by-step explanation: