6. 7P5 = 2520 (nasa pic po ang solution)
7. 4C2 = 6
Solution po ito sa #7
4C2 = 4!/ [2! (4-2)!]
= 4!/ (2! 2!)
= (4 × 3× 2 × 1)/ (2 × 1 × 2× 1)
= 6
Therefore, the value of 4C2 is 6.
8. 7C5 = 21
Solution in #8
Rewrite 7! as 7 • 6 • 5!.
like this haha
7 • 6 •5!
————–
5!(2)!
cancel the common factor 5!.
then next, magiging gan'to na
7•6
——
(2)!
Multiply 7 by 6 = 42. then ganito mo siya isusulat
-----> 42
——–
and next, simplify the denominator...
Divide the 42 by 2 = 21
9. 8C8 = 1
Subtract 8 from 8 then simplify, ganito.
-----> 8!
—————
8!(0)!
= 1
10. 8C1 = 28 (nasa pic din po ang solution)
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Answers & Comments
6. 7P5 = 2520 (nasa pic po ang solution)
7. 4C2 = 6
Solution po ito sa #7
4C2 = 4!/ [2! (4-2)!]
= 4!/ (2! 2!)
= (4 × 3× 2 × 1)/ (2 × 1 × 2× 1)
= 6
Therefore, the value of 4C2 is 6.
8. 7C5 = 21
Solution in #8
Rewrite 7! as 7 • 6 • 5!.
like this haha
7 • 6 •5!
————–
5!(2)!
cancel the common factor 5!.
then next, magiging gan'to na
7•6
——
(2)!
Multiply 7 by 6 = 42. then ganito mo siya isusulat
-----> 42
——–
(2)!
and next, simplify the denominator...
Divide the 42 by 2 = 21
9. 8C8 = 1
Subtract 8 from 8 then simplify, ganito.
-----> 8!
—————
8!(0)!
= 1
10. 8C1 = 28 (nasa pic din po ang solution)