Answer:
Calculate the emf of the cell in which of the following reaction takes place:
Ni(s)+2Ag
+
(0.002M)→Ni
2+
(0.160M)+2Ag(s)
[Given that E
cell
∘
=1.05V]
Explanation:
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Answer:
Calculate the emf of the cell in which of the following reaction takes place:
Ni(s)+2Ag
+
(0.002M)→Ni
2+
(0.160M)+2Ag(s)
[Given that E
cell
∘
=1.05V]
Explanation:
please mark me as branlist