Verified answer

SOLUTION:

Step 1: List the given values.

[tex]\begin{aligned} & P = \text{0.978 atm} \\ & T = 25^{\circ}\text{C} = \text{298.15 K} \\ & MM = \text{16.042 g/mol} \end{aligned}[/tex]

Step 2: Calculate the density.

[tex]\begin{aligned} d & = \frac{(P)(MM)}{RT} \\ & = \frac{(\text{0.978 atm})(\text{16.042 g/mol})}{\left(0.082057 \: \dfrac{\text{L}\cdot\text{atm}}{\text{mol}\cdot\text{K}}\right)(\text{298.15 K})} \\ & = \boxed{\text{0.6413 g/L}} \end{aligned}[/tex]

Hence, the density of methane gas at 25°C and 0.978 atm is 0.6413 g/L.

[tex]\\[/tex]

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