The figure is given here.
To find:
Find the area of shaded region
Explanation:
First find the area of square.
Side of square = 10m.
So,
[tex] \rm{Area \: of \: square=side²} \\ \rm{ = 10²} \\ \rm{ = 100m²}[/tex]
Now find the area of the triangle in the given figure.
Base = 5m
Height = 5m
[tex] \rm{Area \: of \: trinagle = \frac{1}{2} \times base \times height} \\ = \frac{1}{2} \times 5 \times 5 \\ = \rm{ \frac{25}{2} {m}^{2} }[/tex]
There are two triangle with same base and height.
So, the area of another triangle is same
[tex] \rm{\frac{25}{2} {m}^{2} }.[/tex]
Therefore,
Area of shaded region is,
[tex] \rm{Area \: of \: shaded \: region=Area \: of \: square \: -Area \: of \: first \: triangle-Area \: of \: second \: triangle} \\ = 100 - \frac{25}{2} - \frac{25}{2} \\ = \frac{200 - 25 - 25}{2} \\ = \frac{150}{2} \\ \rm = 75 {m}^{2} [/tex]
Final answer: The area of shaded region is
[tex] \rm{75m^{2} .1}[/tex]
To find the area of the shaded region,
Find the area of each shape separately.
1) Area of the rectangle is given as,
A₁ = 1 x b= 10 x 3 = 30m²
A₂ = 1 x b= 4 x 5 = 20m²
A³ = 1x b= 18 x 4 = 72m²
So, the total area is,
A = A₁ + A2+ A3 = A 30+20 + 72 = A = 122m²
Answer: The area of the shaded region is 122 m².
First find the area of each shape included in the given diagram.
There are 3 shapes out of which 1) and 3) are identical.
1) Area of square is,
A¹=side²=5² =25m²
2) area of the rectangle,
A₂1x b= 19 x 5 = 95m² =
The total area is,
A= 2A¹ + A²
A = 2(25) + 95 A = 145m²
The shaded region is half of the whole shape.
Area =
[tex] \rm{ \frac{A}{2} = \frac{145}{5} = 72.5 {m}^{2} }[/tex]
= 72.5m2
Answer: The area of the shaded region is 72.5 m².
First Pic Second Diagram (ii) and Second Pic Third Diagram (iii)
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Answers & Comments
Verified answer
i)
Given:
The figure is given here.
To find:
Find the area of shaded region
Explanation:
First find the area of square.
Side of square = 10m.
So,
[tex] \rm{Area \: of \: square=side²} \\ \rm{ = 10²} \\ \rm{ = 100m²}[/tex]
Now find the area of the triangle in the given figure.
Base = 5m
Height = 5m
So,
[tex] \rm{Area \: of \: trinagle = \frac{1}{2} \times base \times height} \\ = \frac{1}{2} \times 5 \times 5 \\ = \rm{ \frac{25}{2} {m}^{2} }[/tex]
There are two triangle with same base and height.
So, the area of another triangle is same
[tex] \rm{\frac{25}{2} {m}^{2} }.[/tex]
Therefore,
Area of shaded region is,
[tex] \rm{Area \: of \: shaded \: region=Area \: of \: square \: -Area \: of \: first \: triangle-Area \: of \: second \: triangle} \\ = 100 - \frac{25}{2} - \frac{25}{2} \\ = \frac{200 - 25 - 25}{2} \\ = \frac{150}{2} \\ \rm = 75 {m}^{2} [/tex]
Final answer: The area of shaded region is
[tex] \rm{75m^{2} .1}[/tex]
ii)
Given:
To find the area of the shaded region,
Find the area of each shape separately.
1) Area of the rectangle is given as,
A₁ = 1 x b= 10 x 3 = 30m²
A₂ = 1 x b= 4 x 5 = 20m²
A³ = 1x b= 18 x 4 = 72m²
So, the total area is,
A = A₁ + A2+ A3 = A 30+20 + 72 = A = 122m²
Answer: The area of the shaded region is 122 m².
iii)
To find the area of the shaded region,
First find the area of each shape included in the given diagram.
There are 3 shapes out of which 1) and 3) are identical.
1) Area of square is,
A¹=side²=5² =25m²
2) area of the rectangle,
A₂1x b= 19 x 5 = 95m² =
The total area is,
A= 2A¹ + A²
A = 2(25) + 95 A = 145m²
The shaded region is half of the whole shape.
Area =
[tex] \rm{ \frac{A}{2} = \frac{145}{5} = 72.5 {m}^{2} }[/tex]
= 72.5m2
Answer: The area of the shaded region is 72.5 m².
First Pic Second Diagram (ii) and Second Pic Third Diagram (iii)