Calculate the area of the designed region common between the two quadrants of circles of radius 8 cm each. ( figure given in attachment)
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Area of shaded region =2× Area of segment BD
Area of shaded region =2× Area of segment BDConsidering the quadrant ABD,
Area of shaded region =2× Area of segment BDConsidering the quadrant ABD,Area of quadrant ABD=
Area of shaded region =2× Area of segment BDConsidering the quadrant ABD,Area of quadrant ABD= 4
Area of shaded region =2× Area of segment BDConsidering the quadrant ABD,Area of quadrant ABD= 4π×r
Area of shaded region =2× Area of segment BDConsidering the quadrant ABD,Area of quadrant ABD= 4π×r 2
Area of shaded region =2× Area of segment BDConsidering the quadrant ABD,Area of quadrant ABD= 4π×r 2
Area of shaded region =2× Area of segment BDConsidering the quadrant ABD,Area of quadrant ABD= 4π×r 2
Area of shaded region =2× Area of segment BDConsidering the quadrant ABD,Area of quadrant ABD= 4π×r 2 =
Area of shaded region =2× Area of segment BDConsidering the quadrant ABD,Area of quadrant ABD= 4π×r 2 = 4
Area of shaded region =2× Area of segment BDConsidering the quadrant ABD,Area of quadrant ABD= 4π×r 2 = 41
Area of shaded region =2× Area of segment BDConsidering the quadrant ABD,Area of quadrant ABD= 4π×r 2 = 41
Area of shaded region =2× Area of segment BDConsidering the quadrant ABD,Area of quadrant ABD= 4π×r 2 = 41 ×3.14×8×8=50.24cm
Area of shaded region =2× Area of segment BDConsidering the quadrant ABD,Area of quadrant ABD= 4π×r 2 = 41 ×3.14×8×8=50.24cm 2
Area of shaded region =2× Area of segment BDConsidering the quadrant ABD,Area of quadrant ABD= 4π×r 2 = 41 ×3.14×8×8=50.24cm 2
Area of shaded region =2× Area of segment BDConsidering the quadrant ABD,Area of quadrant ABD= 4π×r 2 = 41 ×3.14×8×8=50.24cm 2 Area of △ABD =
Area of shaded region =2× Area of segment BDConsidering the quadrant ABD,Area of quadrant ABD= 4π×r 2 = 41 ×3.14×8×8=50.24cm 2 Area of △ABD = 2
Area of shaded region =2× Area of segment BDConsidering the quadrant ABD,Area of quadrant ABD= 4π×r 2 = 41 ×3.14×8×8=50.24cm 2 Area of △ABD = 21
Area of shaded region =2× Area of segment BDConsidering the quadrant ABD,Area of quadrant ABD= 4π×r 2 = 41 ×3.14×8×8=50.24cm 2 Area of △ABD = 21
Area of shaded region =2× Area of segment BDConsidering the quadrant ABD,Area of quadrant ABD= 4π×r 2 = 41 ×3.14×8×8=50.24cm 2 Area of △ABD = 21 ×8×8=32cm
Area of shaded region =2× Area of segment BDConsidering the quadrant ABD,Area of quadrant ABD= 4π×r 2 = 41 ×3.14×8×8=50.24cm 2 Area of △ABD = 21 ×8×8=32cm 2
Area of shaded region =2× Area of segment BDConsidering the quadrant ABD,Area of quadrant ABD= 4π×r 2 = 41 ×3.14×8×8=50.24cm 2 Area of △ABD = 21 ×8×8=32cm 2
Area of shaded region =2× Area of segment BDConsidering the quadrant ABD,Area of quadrant ABD= 4π×r 2 = 41 ×3.14×8×8=50.24cm 2 Area of △ABD = 21 ×8×8=32cm 2 ∴ Area of segment BD = Area of quadrant ABD − Area of △ABD
Area of shaded region =2× Area of segment BDConsidering the quadrant ABD,Area of quadrant ABD= 4π×r 2 = 41 ×3.14×8×8=50.24cm 2 Area of △ABD = 21 ×8×8=32cm 2 ∴ Area of segment BD = Area of quadrant ABD − Area of △ABD =50.24−32=18.24cm
Area of shaded region =2× Area of segment BDConsidering the quadrant ABD,Area of quadrant ABD= 4π×r 2 = 41 ×3.14×8×8=50.24cm 2 Area of △ABD = 21 ×8×8=32cm 2 ∴ Area of segment BD = Area of quadrant ABD − Area of △ABD =50.24−32=18.24cm 2
Area of shaded region =2× Area of segment BDConsidering the quadrant ABD,Area of quadrant ABD= 4π×r 2 = 41 ×3.14×8×8=50.24cm 2 Area of △ABD = 21 ×8×8=32cm 2 ∴ Area of segment BD = Area of quadrant ABD − Area of △ABD =50.24−32=18.24cm 2
Area of shaded region =2× Area of segment BDConsidering the quadrant ABD,Area of quadrant ABD= 4π×r 2 = 41 ×3.14×8×8=50.24cm 2 Area of △ABD = 21 ×8×8=32cm 2 ∴ Area of segment BD = Area of quadrant ABD − Area of △ABD =50.24−32=18.24cm 2 ∴ Area of shaded region =2×18.24=36.48cm
Area of shaded region =2× Area of segment BDConsidering the quadrant ABD,Area of quadrant ABD= 4π×r 2 = 41 ×3.14×8×8=50.24cm 2 Area of △ABD = 21 ×8×8=32cm 2 ∴ Area of segment BD = Area of quadrant ABD − Area of △ABD =50.24−32=18.24cm 2 ∴ Area of shaded region =2×18.24=36.48cm 2