Answer:
Step 1:Molecular mass of calcium carbonate (CaCO3 ) = 40 + 12 + 16 ✕ 3 = 100 u
Step 2: Atomic mass of calcium = 40 u
Mass of calcium in 1 mole of CaCO3 = 40 grams
Step 3:Mass percentage of an element = mass of an element/mass of compound ✕ 100
Percentage of calcium = 40/100 ✕ 100 = 40%
Final Answer:
The percentage of calcium in calcium carbonate is 40%.
Copyright © 2024 EHUB.TIPS team's - All rights reserved.
Answers & Comments
Verified answer
Answer:
Step 1:Molecular mass of calcium carbonate (CaCO3 ) = 40 + 12 + 16 ✕ 3 = 100 u
Step 2: Atomic mass of calcium = 40 u
Mass of calcium in 1 mole of CaCO3 = 40 grams
Step 3:Mass percentage of an element = mass of an element/mass of compound ✕ 100
Percentage of calcium = 40/100 ✕ 100 = 40%
Final Answer:
The percentage of calcium in calcium carbonate is 40%.