Verified answer

SOLUTION:

The molar mass of CO₂ is 44.0095 g/mol.

The volume of an ideal gas at STP is 22.414 L.

[tex]\begin{aligned} V_{\text{CO}_2} & = \text{88.4 g} \: \text{CO}_2 \times \frac{\text{1 mol} \: \text{CO}_2}{\text{44.0095 g} \: \text{CO}_2} \times \frac{\text{22.414 L}}{\text{1 mol} \: \text{CO}_2} \\ & = \boxed{\text{45.0 L}} \end{aligned}[/tex]

Hence, the volume of 88.4 g of CO₂ at STP is 45.0 L.

[tex]\\[/tex]

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