To calculate the moles of water formed when 2.5 grams of H2O2 decomposes, you can follow these steps:
a. Calculate moles of H2O2:
1. Find the molar mass of H2O2 (hydrogen peroxide). It consists of 2 hydrogen atoms (2 g/mol) and 2 oxygen atoms (16 g/mol), so the molar mass is 2 * 2 + 2 * 16 = 2 + 32 = 34 g/mol.
2. Now, calculate the moles of H2O2 using the formula:
Moles = Mass (grams) / Molar Mass
Moles = 2.5 g / 34 g/mol ≈ 0.0735 moles of H2O2
b. Calculate moles of oxygen:
1. In the decomposition of H2O2, one mole of H2O2 produces one mole of oxygen.
2. So, the moles of oxygen formed will also be approximately 0.0735 moles.
c. Calculate the mass of oxygen liberated:
1. Use the moles of oxygen calculated in step b to find the mass of oxygen using the molar mass of oxygen (O2), which is 32 g/mol.
2. Mass (grams) = Moles × Molar Mass
3. Mass = 0.0735 moles × 32 g/mol = 2.34 grams
So, when 2.5 grams of H2O2 decompose, approximately 0.0735 moles of water are formed, and 2.34 grams of oxygen are liberated.
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Answer:
To calculate the moles of water formed when 2.5 grams of H2O2 decomposes, you can follow these steps:
a. Calculate moles of H2O2:
1. Find the molar mass of H2O2 (hydrogen peroxide). It consists of 2 hydrogen atoms (2 g/mol) and 2 oxygen atoms (16 g/mol), so the molar mass is 2 * 2 + 2 * 16 = 2 + 32 = 34 g/mol.
2. Now, calculate the moles of H2O2 using the formula:
Moles = Mass (grams) / Molar Mass
Moles = 2.5 g / 34 g/mol ≈ 0.0735 moles of H2O2
b. Calculate moles of oxygen:
1. In the decomposition of H2O2, one mole of H2O2 produces one mole of oxygen.
2. So, the moles of oxygen formed will also be approximately 0.0735 moles.
c. Calculate the mass of oxygen liberated:
1. Use the moles of oxygen calculated in step b to find the mass of oxygen using the molar mass of oxygen (O2), which is 32 g/mol.
2. Mass (grams) = Moles × Molar Mass
3. Mass = 0.0735 moles × 32 g/mol = 2.34 grams
So, when 2.5 grams of H2O2 decompose, approximately 0.0735 moles of water are formed, and 2.34 grams of oxygen are liberated.