Answer:
CaCl2(aq) ------→ Ca2+ + 2Cl-
1 mole of CaCl2. ---→ 3 × 6.022 × 10^23
1332/111 moles of CaCl2 → 1332/111×3×6.022×10^23
→2.2 × 10^25
Therefore,
1332g of CaCl2 will give 2.2 × 10^25 ions
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Answer:
CaCl2(aq) ------→ Ca2+ + 2Cl-
1 mole of CaCl2. ---→ 3 × 6.022 × 10^23
1332/111 moles of CaCl2 → 1332/111×3×6.022×10^23
→2.2 × 10^25
Therefore,
1332g of CaCl2 will give 2.2 × 10^25 ions