Answer:

96-80 = 16

16÷2 = 8

80+8 = 88

96-8 = 88

Answer:

Maximum number of girls and boys in team for a match so that the number of students in each team is the same and no student is left behind is 16.

Step-by-step explanation:

Given that, there are 80 girls and 96 boys in Class 6 of a school.

Now, we have to formed separate teams of maximum number of girls and boys for a match so that the number of students in each team is the same and no student is left behind.

So, maximum number of girls and boys in a team for a match so that the number of students in each team is the same and no student is left behind is HCF (80, 96)

Now, in order to find HCF of 80 and 96, we use method of factorization.

So,

[tex]\sf \: Prime\:factors\:of \: 80 = 2 \times2 \times 2 \times 2 \times 5 = {2}^{4} \times 5 \\ \\ [/tex]

and

[tex]\sf \: Prime\:factors\:of \: 96 = 2 \times2 \times 2 \times 2 \times 2 \times 3 = {2}^{5} \times 3 \\ \\ [/tex]

Thus,

[tex]\sf \: HCF (80, 96) = {2}^{4} \\ \\ [/tex]

[tex]\sf\implies \sf \: HCF (80, 96) = 16 \\ \\ [/tex]

Hence,

Maximum number of girls and boys in a team for a match so that the number of students in each team is the same and no student is left behind is 16.