C. Direction: Using the divisibility rules 2, 5, 10, and 3, 6, 9, list down the factors and encircle all the common factors of the given number.
1. 12 ____________________________________________________________________
24 ____________________________________________________________________
2. 60 ____________________________________________________________________
100 ____________________________________________________________________
3. 18 ____________________________________________________________________
54 ____________________________________________________________________
4. 30 ____________________________________________________________________
120 ____________________________________________________________________
5. 75 ____________________________________________________________________
150 ____________________________________________________________________
1. 12 ____________________________________________________________________
24 ____________________________________________________________________
2. 60 ____________________________________________________________________
100 ____________________________________________________________________
3. 18 ____________________________________________________________________
54 ____________________________________________________________________
4. 30 ____________________________________________________________________
120 ____________________________________________________________________
5. 75 ____________________________________________________________________
150 ____________________________________________________________________
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Answer:
1.12=2 is an even number 12=1+2=3 is 3 can be divided by 3 without a remainder? 3÷3=1 so it's divisible by 6
24=4 is an even number so it's divisible by 2 24=2+4=6 is 6 can be divided by 3 without a remainder? 3÷6=2 yes so it is divisible by 3
2.60=since the last digit of 60 is zero it is divisible by 2,5 and 10
100=since the last digit of 100 is zero it is divisible by 2,5 and 10
3. 18=1+8=9 is 9 can be divided by 9 without a remainder? 9÷9=1 yes so it is divisible by 9
54=4 is an even number so it is divisible by 2 54=5+4=9 is 9 can be divided by 3 without a remainder? 3÷9= 3 yes so it is divisible by 6
4. 30= since the last digit is zero so it is divisible by 2, 5 and 10
120=1+2+0=3 is 3 can be divided by 3 without a remainder? 3÷3=1 yes so it is divisible by 3
5. 75=since the last number of 75 is 5 so it is divisible by 5
150=1+5+0= 6 is 6 can be divided by 3 without a remainder? 3÷6=2 yes so it is divisible by 3
Step-by-step explanation:
3 and 9-if the sum of the digits is can be divided without a remainder it is divisible by 3 or 9
6-if the digits are both divisible by 2 and 3 it is divisible by 6
10-if the last number is 0 it is divisible by 10
5-if the last number is 0 or 5 it is divisible by 5
2-if the last number is 0,2,4,6 and 8 it is divisible by 2