[tex]\large\underline{\sf{Solution-}}[/tex]

Given that, By selling a table for Rs. 1260, the seller loses 10%.

So, we have

Selling Price of table = Rs 1260

Loss % = 10 %

We know,

[tex]\rm \: Cost\:Price = \dfrac{100 \times Selling\:Price}{100 - Loss\%} \\ [/tex]

So, on substituting the values, we get

[tex]\rm \: Cost\:Price = \dfrac{100 \times 1260}{100 - 10} \\ [/tex]

[tex]\rm \: Cost\:Price = \dfrac{126000}{90} \\ [/tex]

[tex]\rm\implies \:Cost\:Price \: = \: Rs \: 1400 \\ [/tex]

Now, we have

Cost Price of table = Rs 1400

Gain % = 25 %

We know,

[tex]\rm \: Selling\:Price = \dfrac{(100 + gain\%) \times Cost\:Price}{100} \\ [/tex]

[tex]\rm \: Selling\:Price = \dfrac{(100 + 25) \times 1400}{100} \\ [/tex]

[tex]\rm \: Selling\:Price =125 \times 14 \\ [/tex]

[tex]\rm\implies \:Selling\:Price \: = \: Rs \: 1750 \\ [/tex]

[tex]\rule{190pt}{2pt}[/tex]

Additional Information :-

[tex]\begin{gathered}\: \: \: \: \: \: \begin{gathered}\begin{gathered} \footnotesize{\boxed{ \begin{array}{cc} \small\underline{\frak{\pmb{ \red{More \: Formulae}}}} \\ \\ \bigstar \: \bf{Gain = \sf S.P. \: – \: C.P.} \\ \\ \bigstar \:\bf{Loss = \sf C.P. \: – \: S.P.} \\ \\ \bigstar \: \bf{Gain \: \% = \sf \Bigg( \dfrac{Gain}{C.P.} \times 100 \Bigg)\%} \\ \\ \bigstar \: \bf{Loss \: \% = \sf \Bigg( \dfrac{Loss}{C.P.} \times 100 \Bigg )\%} \\ \\ \\ \bigstar \: \bf{S.P. = \sf\dfrac{(100+Gain\%) or(100-Loss\%)}{100} \times C.P.} \\ \: \end{array} }}\end{gathered}\end{gathered}\end{gathered}[/tex]

Verified answer

Information provided with us:

Selling price of table

• ➡ 1260

Loss percent of table

• ➡ 10%.

What we have to find :

• ➡ At what price should he sell it so as to gain 25%

Solution :

[tex] \rm \implies \: C. P =( \dfrac{100}{100 - L \: \%} \times \:S . P )[/tex]

Note :

➡ C.P = Cost Price

➡ L % = Lost percent

➡ S .P = Selling Price

Now :

• We know the given values

➡ L % = 10

➡S.P = 1230

Here :

• ➡ Place the given values in this formula of C.P and solve

[tex]\rm \implies \: C. P =( \dfrac{100}{100 - 10 \: \%} \times \:1260 )[/tex]

[tex]\rm \implies \: C. P =( \dfrac{100}{90} \times \:1260 )[/tex]

[tex]\rm \implies \: C. P =( \dfrac{100 \times 1260}{90} )[/tex]

[tex]\rm \implies \: C. P =( \dfrac{126000}{90} )[/tex]

[tex]\bf \implies \: C. P = 1,400 \: Rs [/tex]

Now :

• We know the given values

➡ C.P = Cost price = 1,400 Rs

➡ Gain % = 25 %

Here :

• ➡ Place the given values in this formula of S.P and solve

[tex]\rm \implies \: S.P=( \dfrac{100 +G \: \% }{100} \times \:C. P)[/tex]

[tex]\rm \implies \: S.P=( \dfrac{100 +25\: \% }{100} \times \:1,400)[/tex]

[tex]\rm \implies \: S.P=( \dfrac{125 }{100} \times \:1,400)[/tex]

[tex]\rm \implies \: S.P=( \dfrac{125 \times \:1,400}{100} )[/tex]

[tex]\rm \implies \: S.P=( \dfrac{175000}{100} )[/tex]

[tex]\bf \implies \: S.P=1,750[/tex]

Therefore :

• ➡ The required price should he sell it so as to gain 25% is 1,750 Rs .

Formula used :

[tex]\rm \implies \: C. P =( \dfrac{100}{100 - L \: \%} \times \:S . P )[/tex]

[tex]\rm \implies \: S.P=( \dfrac{100 +G \: \% }{100} \times \:C. P)[/tex]