Verified answer

Answer:

Here, (-) sign precedes both the parenthesis, so we remove it and change the sign of each term within

∴−2(x2−y2+xy)−3(x2+y2−xy)

=−2x2+2y2−2xy−3x2−3y2+3xy

Rearranging and collecting the like terms, we get:

=−2x2−3x2+2y2−3y2−2xy+3xy

=(−2−3)x2+(2−3)y2+(−2+3)xy

=−5x2−y2+xy