B.Supply the missing number to complete the expanded form.
1. 24.253 = (2×__)+(4×__)+(2×__)+(5×__)+ (3×__) =20+__+__+__+__
2. 0.4629 = (__×0.1)+(__×0.01)+(__×0.001) +(__×0.0001) =__+__+__+__
3. 2.1675 =(2×__)+(1×__)+(6×__)+(7×__)+(5×) = 2+__+__+__+__
Answers & Comments
B.Supply the missing number to complete the expanded form.
1. 24.253 = (2×__)+(4×__)+(2×__)+(5×__)+ (3×__) =20+__+__+__+__
2. 0.4629 = (__×0.1)+(__×0.01)+(__×0.001) +(__×0.0001) =__+__+__+__
3. 2.1675 =(2×__)+(1×__)+(6×__)+(7×__)+(5×) = 2+__+__+__+__
1) 24.253 = (2 × 10) + (4 × 1) + (2 × 0.1) + (5 × 0.01) + (3 × 0.001) = 20 + 4 + 0.2 + 0.05 + 0.003
2) 0.4629 = (4 × 0.1) + (6 × 0.01) + (2 × 0.001) + (9 × 0.0001) = 0.4 + 0.06 + 0.002 + 0.0009
3) 2.1675 = (2 × 1) + (1 × 0.1) + (6 × 0.01) + (7 × 0.001) + (5 × 0.0001) = 2 + 0.1 + 0.06 + 0.007 + 0.0005