First Solve the area of 2 shaded triangles in the left and right figure which is (formula: a=b×h/2, [4×10/2=20]) 20 cm² each. then solve the area middle rectangle which has length of 10cm and width of 2 cm which resulted to 20cm². then add the total area (20cm² in the middle rectangle, 20 cm² in the right triangle and 20cm² in the left triangle) which gives 60cm².
Answers & Comments
Answer:
60 cm²
Step-by-step explanation:
(Using MDAS rule)
First Solve the area of 2 shaded triangles in the left and right figure which is (formula: a=b×h/2, [4×10/2=20]) 20 cm² each. then solve the area middle rectangle which has length of 10cm and width of 2 cm which resulted to 20cm². then add the total area (20cm² in the middle rectangle, 20 cm² in the right triangle and 20cm² in the left triangle) which gives 60cm².
Answer:
a(lb+bh+ho)
=2(4×4+4×10+10×4)
=2+(1040+40+40)cm²
=2(96)cm²
=192cm²