∠BOC=2∠BAC, the angle formed at the centre is twice the angle formed at the circumference. Therefore, ∠BOC=2n
∠OCB=m
Since, OB = OC = radius of the circle = m
Thus, in Δ OBC,
∠OCB+∠OBC+∠BOC=180∘
2m+2n=180
⇒m+n=90
∠BOC=2∠BAC, the angle formed at the centre is twice the angle formed at the circumference.
Therefore, ∠BOC=2n
∠OCB=m
Since, OB = OC = radius of the circle = m
Thus, in Δ OBC,
∠OCB+∠OBC+∠BOC=180∘
2m+2n=180
⇒m+n=90
∠BOC=2∠BAC, the angle formed at the centre is twice the angle formed at the circumference.
Therefore, ∠BOC=2n
∠OCB=m
Since, OB = OC = radius of the circle = m
Thus, in Δ OBC,
∠OCB+∠OBC+∠BOC=180∘
2m+2n=180
⇒m+n=90
∠BOC=2∠BAC, the angle formed at the centre is twice the angle formed at the circumference.
Therefore, ∠BOC=2n
∠OCB=m
Since, OB = OC = radius of the circle = m
Thus, in Δ OBC,
∠OCB+∠OBC+∠BOC=180∘
2m+2n=180
⇒m+n=90
∠BOC=2∠BAC, the angle formed at the centre is twice the angle formed at the circumference.
Therefore, ∠BOC=2n
∠OCB=m
Since, OB = OC = radius of the circle = m
Thus, in Δ OBC,
∠OCB+∠OBC+∠BOC=180∘
2m+2n=180
⇒m+n=90
∠BOC=2∠BAC, the angle formed at the centre is twice the angle formed at the circumference.
Therefore, ∠BOC=2n
∠OCB=m
Since, OB = OC = radius of the circle = m
Thus, in Δ OBC,
∠OCB+∠OBC+∠BOC=180∘
2m+2n=180
⇒m+n=90
∠OCB=m
Since, OB = OC = radius of the circle = m
Thus, in Δ OBC,
∠OCB+∠OBC+∠BOC=180∘
2m+2n=180
⇒m+n=90
∠BOC=2∠BAC, the angle formed at the centre is twice the angle formed at the circumference.
Therefore, ∠BOC=2n
∠OCB=m
Since, OB = OC = radius of the circle = m
Thus, in Δ OBC,
∠OCB+∠OBC+∠BOC=180∘
2m+2n=180
⇒m+n=90
∠BOC=2∠BAC, the angle formed at the centre is twice the angle formed at the circumference.
Therefore, ∠BOC=2n
∠OCB=m
Since, OB = OC = radius of the circle = m
Thus, in Δ OBC,
∠OCB+∠OBC+∠BOC=180∘
2m+2n=180
⇒m+n=90
∠BOC=2∠BAC, the angle formed at the centre is twice the angle formed at the circumference.
Therefore, ∠BOC=2n
∠OCB=m
Since, OB = OC = radius of the circle = m
Thus, in Δ OBC,
∠OCB+∠OBC+∠BOC=180∘
2m+2n=180
⇒m+n=90
∠BOC=2∠BAC, the angle formed at the centre is twice the angle formed at the circumference.
Therefore, ∠BOC=2n
∠OCB=m
Since, OB = OC = radius of the circle = m
Thus, in Δ OBC,
∠OCB+∠OBC+∠BOC=180∘
2m+2n=180
⇒m+n=90
∠BOC=2∠BAC, the angle formed at the centre is twice the angle formed at the circumference.
Therefore, ∠BOC=2n
∠OCB=m
Since, OB = OC = radius of the circle = m
Thus, in Δ OBC,
∠OCB+∠OBC+∠BOC=180∘
2m+2n=180
⇒m+n=90
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