The Bohr magneton is the magnitude of the magnetic dipole moment of an electron orbiting an atom with such angular momentum. According to the Bohr model, this is the ground state, i.e. the state of lowest possible energy.
Explanation:
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In the Bohr model of the atom, for an electron that is in the orbit of lowest energy, its orbital angular momentum has magnitude equal to the reduced Planck constant, denoted ħ. The Bohr magneton is the magnitude of the magnetic dipole moment of an electron orbiting an atom with this angular momentum. The Bohr magneton, named for the 20th-century Danish physicist Niels Bohr, is equal to about 9.274 × 10−21 erg per gauss per particle. The nuclear magneton, calculated by using the mass of the proton (rather than that of the electron, used to calculate the Bohr magneton).
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Answer:
The Bohr magneton is the magnitude of the magnetic dipole moment of an electron orbiting an atom with such angular momentum. According to the Bohr model, this is the ground state, i.e. the state of lowest possible energy.
Explanation:
Hope my answer is helpful to you and please brainliest me
Answer:
In the Bohr model of the atom, for an electron that is in the orbit of lowest energy, its orbital angular momentum has magnitude equal to the reduced Planck constant, denoted ħ. The Bohr magneton is the magnitude of the magnetic dipole moment of an electron orbiting an atom with this angular momentum. The Bohr magneton, named for the 20th-century Danish physicist Niels Bohr, is equal to about 9.274 × 10−21 erg per gauss per particle. The nuclear magneton, calculated by using the mass of the proton (rather than that of the electron, used to calculate the Bohr magneton).
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