Answer:
ax² + bx +c =0
zeroes α,β
sum of roots = α+β = -b/a
products of roots = αβ = c/a
1/α - 1/β = β-α / αβ ............(1)
β-a = √(b² - 4ac/a² ) putting this value
1/α - 1/β = √(b²-4ac/a²) / c/a = √b²-4ac / c
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Answer:
ax² + bx +c =0
zeroes α,β
sum of roots = α+β = -b/a
products of roots = αβ = c/a
1/α - 1/β = β-α / αβ ............(1)
β-a = √(b² - 4ac/a² ) putting this value
1/α - 1/β = √(b²-4ac/a²) / c/a = √b²-4ac / c
Hope it will be helpful to you............
Please!!! mark my answer as Brainliest............