Question only for @mathdude500 or @StarFighter or any eminent person.
A and B are two points on the x-axis and y-axis respectively. P (2, – 3) is the mid point of AB. Find the:
(i) the co-ordinates of A and B.
(ii) the slope of the line AB.
(iii) the equation of the line AB.
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A and B are two points on the x-axis and y-axis respectively. P (2, – 3) is the mid point of AB. Find the:
(i) the co-ordinates of A and B.
(ii) the slope of the line AB.
(iii) the equation of the line AB.
Want quality answers for this question!
Spam/Irrelevant answers= Your account /ban.
Thank You
~ Ex-apprentice moderator
Answers & Comments
Given :-
P(2, -3)
Assume that,
then,
[tex]2 = \frac{x + 0}{2} \\ = > x = 2 \times 2 \\ = > x = 4[/tex]
and
[tex] - 3 = \frac{0 + y}{2} \\ = > - 3 \times 2 = y \\ = > y = - 6[/tex]
So, [tex]x = 4[/tex] and [tex]y = - 6[/tex]
Now, as per sub-questions,
_____________________
(i) Coordinates are :-
A(4,0)
B(0, -6)
( I directly substituted the values )
______________________
(ii) Slope of AB =
[tex] \frac{y_2 - y_1}{x_2 - x_1} \\ [/tex]
[tex] = > \frac{ - 6 - 0}{0 - 4} \\ = > \frac{ - 6}{ - 4} \\ = > \frac{6}{4} \\ \\ = > \frac{3}{2}[/tex]
_______________________
(iii) Check attached image for explanation.