Answer:

CO2 + 6 H2O → C6H12O6 + 6 O2 (Balanced)

SiCl4 + 4 H2O → H4SiO4 + 4 HCl (Balanced)

2 Al + 6 HCl → 2 AlCl3 + 3 H2 (Balanced)

Na2CO3 + 2 HCl → 2 NaCl + H2O + CO2 (Balanced)

C7H6O2 + 9 O2 → 7 CO2 + 3 H2O (Balanced)

KClO3 → KClO4 + KCl (Not balanced)

To balance this equation, we need to change the coefficient in front of KClO3.

2 KClO3 → KClO4 + KCl (Balanced)

Verified answer

Explanation:

CO2 + H2O → C6H12O6 + O2.

- Count the number of atoms for each element on both sides of the equation.

- Carbon: 1 on the left, 6 on the right

- Hydrogen: 2 on the left, 12 on the right

- Oxygen: 3 on the left, 6 on the right

- Balance the carbon atoms by placing a coefficient of 6 in front of CO2 on the left.

- CO2 + 6H2O → C6H12O6 + O2

- Balance the hydrogen atoms by placing a coefficient of 12 in front of H2O on the left.

- CO2 + 6H2O → C6H12O6 + O2

- Balance the oxygen atoms by placing a coefficient of 6 in front of O2 on the right.

- CO2 + 6H2O → C6H12O6 + 6O2

SiCl4 + H2O → H4SiO4 + HCl.

- Count the number of atoms for each element on both sides of the equation.

- Silicon: 1 on the left, 1 on the right

- Chlorine: 4 on the left, 1 on the right

- Hydrogen: 2 on the left, 4 on the right

- Oxygen: 1 on the left, 4 on the right

- Balance the hydrogen atoms by placing a coefficient of 4 in front of HCl on the right.

- SiCl4 + H2O → H4SiO4 + 4HCl

- Balance the chlorine atoms by placing a coefficient of 4 in front of HCl on the left.

- SiCl4 + 2H2O → H4SiO4 + 4HCl

- Balance the oxygen atoms by placing a coefficient of 4 in front of H2O on the right.

- SiCl4 + 2H2O → H4SiO4 + 4HCl

Al + HCl → AlCl3 + H2.

- Count the number of atoms for each element on both sides of the equation.

- Aluminum: 1 on the left, 1 on the right

- Chlorine: 1 on the left, 3 on the right

- Hydrogen: 1 on the left, 2 on the right

- Balance the chlorine atoms by placing a coefficient