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How much pure water is to be mixed with a 60 L of 70% alcohol solution to get 30% alcohol solution?
How much pure water is to be mixed with a 60 L of 70% alcohol solution to get 30% alcohol solution?
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You would need to add 12 liters of water, as 60 liters X 60% alcohol is 36 liters of pure alcohol, so double that amount would be the total needed for half, 72–60=12.
You would need to add 30 liters of 30% alcohol, as 30% of 30 is 9, plus the 36 we already know gets us 45 liters of pure alcohol, and since we added 30 to 60 that brings it to 90 total liters of 50% alcohol.
Answer:
You would need to add 12 liters of water, as 60 liters X 60% alcohol is 36 liters of pure alcohol, so double that amount would be the total needed for half, 72–60=12.
You would need to add 30 liters of 30% alcohol, as 30% of 30 is 9, plus the 36 we already know gets us 45 liters of pure alcohol, and since we added 30 to 60 that brings it to 90 total liters of 50% alcohol.
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