[tex]42a^5b^4[/tex] = (2a²b) (3ab)(___)
Solve for the missing numerical coefficient:
[tex] \displaystyle \frac{42}{2(3)} = \frac{42}{6} = \boxed{7} [/tex]
Solve for the missing literal coefficients:
[tex] \displaystyle \frac{a^5}{a^2(a)} = \frac{a^5}{a^3} = \boxed{a^2}[/tex]
[tex] \displaystyle \frac{b^4}{b(b)} = \frac{b^4}{b^2} = \boxed{b^2}[/tex]
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Answers & Comments
Question:
[tex]42a^5b^4[/tex] = (2a²b) (3ab)(___)
Solution/s:
Solve for the missing numerical coefficient:
[tex] \displaystyle \frac{42}{2(3)} = \frac{42}{6} = \boxed{7} [/tex]
Solve for the missing literal coefficients:
[tex] \displaystyle \frac{a^5}{a^2(a)} = \frac{a^5}{a^3} = \boxed{a^2}[/tex]
[tex] \displaystyle \frac{b^4}{b(b)} = \frac{b^4}{b^2} = \boxed{b^2}[/tex]
Answer: [tex] (7a^2b^2) [/tex]