B. Solve the following problem.1. One side of a cube measures 5 cm. Solve for it...

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November 2021 1 9 Report

B. Solve the following problem.

1. One side of a cube measures 5 cm. Solve for its surface areas?

2. Find the total surface area of the can of paint whose radius is 13 cm and 15 cm
in height.

3. The gardener regularly maintains circular garden whose diameter is 7 meters.
What is the area of the garden?

4. The lateral area of a cylinder is 95 cm². The height is 8 cm. What is the radius?

5. Lani bakes a rectangular cake that is 23cm wide, 33cm long and 5 cm high. She
removes the cake from the pan to frost it. How many squares centimeters of
frosting does she needs?

Answers & Comments

SugarCream

Number 1:-

Area:- $\sf 6 {a}^{2}$

$\sf = 6 \times 5^{2}$
$\sf = 6 \times 5 \times 5$
$\sf = 150 \: \green✓$

$\:$

Number 2:-

Surface Area:- $\sf 2\pi rh + 2\pi {r}^{2}$

$\sf 2\pi \times 13 \times 15 = 1225.22 \: cm ^{2}$
$\sf 2\pi \times {13}^{2} = 1061.85 \: {cm}^{2}$
$\sf 1061.85 \: {cm}^{2} + 1225.22 \: {cm}^{2}$
$\sf = 2287.07 \: cm ^{2} \: \green✓$

$\:$

Number 3:-

Area:- $\sf \pi r ^{2}$

$\sf = \frac{d}{2}$
$\sf = \frac{7}{2}$
$\sf = 3.5 \: cm$
$\sf = 3.14 \times (3.5^{2} )$
$\sf = 38.465 \: cm$
$\sf = 38 \: cm \: \green✓$

$\:$

Number 4:-

Area:- $\sf 2\pi rh + 2\pi r ^{2}$

$= \sf \frac{1}{5} \sqrt{ {h}^{2} + 2 \: \frac{a}{\pi} - \frac{h}{2} = \frac{1}{2} }$
$= \sf \sqrt{ {8}^{2} + 2 \: \frac{95}{\pi} - \frac{8}{2} }$
$= \sf 1.57 \: \green✓$

$\:$

Number 5:-

Square Centimeters:- $\sf l \times w \times h$

$\sf = 23 \times 33 \times 5$
$\sf = 3795 \: square \: cm \: \green ✓$

____________________________________________

Answers:-

150
2287.07 cm^2
38 cm
1.57
3795 square cm

russeljoiceolino123 tama po bato ask ko lang po

SugarCream Yep.

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