B. Find the solutions of the following quadratic using indicated method.(with so...

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October 2022 1 2 Report

B. Find the solutions of the following quadratic using indicated method.

(with solutions po)

c.using completing the square
1. x² + 2x - 8 = 0

2. x² - 10x = -9

d.using quadratic formula
1. x² + 4x - 5 = 0

2. 2x² - 3x = 5

Help me of this please, need a answer rn. Thank you.

Answers & Comments

joeliaquino

1. x² + 2x - 8 = 0

$\\ \\ {x}^{2} + 2x - 8 = 0 \\ \\ {x}^{2} + 2x = 8 \\ \\ {x}^{2} + 2x + {1}^{2} = 8 + {1}^{2} \\ \\ {(x + 1)}^{2} = 9 \\ \\ x _{1} = - 4 \: \: \: or \: \: x _{2} = 2$

2. x² - 10x = -9

$\\ {x}^{2} - 10x = - 9 \\ \\ {x}^{2} - 10x + {( \frac{10}{2}) }^{2} = - 9 + {( \frac{10}{2}) }^{2} \\ \\ {(x - \frac{10}{2} )}^{2} = 16 \\ \\ {(x - 5)}^{2} = 16 \\ \\ x _{1} = 1 \: \: or \: \: x _{2} = 9$

1. x² + 4x - 5 = 0

$\\ {x}^{2} + 4x - 5 = 0 \\ \\ x = \frac{ - 4± \sqrt{ {4}^{2} - 4(1) - 5) } }{2(1)} \\ \\ x = \frac{ - 4± \sqrt{ 16 + 20 } }{2} \\ \\ x = \frac{ - 4± \sqrt{ 36 } }{2} \\ \\x = \frac{ - 4± 6 }{2} \\ \\ \\ x = \frac{ - 4 + 6 }{2} \: \: \: or \: \: \: x = \frac{ - 4 - 6 }{2}$

2. 2x² - 3x = 5

$\\ {2x}^{2} - 3x = 5 \\ \\ {2x}^{2} - 3x - 5 = 0 \\ \\ x = \frac{ - ( - 3)± \sqrt{( - 3) {}^{2} - 4(2)( - 5)} }{2(2)} \\ \\ x = \frac{3± \sqrt{9 + 40} }{4} \\ \\ x = \frac{3± \sqrt{49} }{4} \\ \\ x = \frac{3±7}{4} \\ \\ x = \frac{3 + 7}{4} \: \: or \: \: x = \frac{3 - 7}{4} \\ \\ \\ x _{1} = - 1 \: \: \: or \: \: \: x _{2} = \frac{5}{2}$

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