1) 3x² - 4 = 2x- 9
First, transpose 2x - 9 to the left side.
Then, solve the -4+9.
Thus, the standard form is 3x²-2x+5=0
2) 2(2x-5) = 4x (x - 1)
First, solve the 2(2x-5) and 4x(x-1).
Second, transpose 4x²-4x to the left side.
Lastly, solve the 4x+4x.
Therefore, the standard form is 4x²+8x-10=0.
NOTE:
1.) 3x2 - 4 = 2x-9
2.) 2(2x-5) = 4x (x - 1)
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QUADRATIC EQUATION
Direction: Express the given equation in standard form (ax² +bx+c = 0). Identify the values of a, b, and c.
1) 3x² - 4 = 2x- 9
First, transpose 2x - 9 to the left side.
Then, solve the -4+9.
Thus, the standard form is 3x²-2x+5=0
2) 2(2x-5) = 4x (x - 1)
First, solve the 2(2x-5) and 4x(x-1).
Second, transpose 4x²-4x to the left side.
Lastly, solve the 4x+4x.
Therefore, the standard form is 4x²+8x-10=0.
NOTE:
1.) 3x2 - 4 = 2x-9
3x²-2x+5=0
a = 3
b = -2
c = 5
2.) 2(2x-5) = 4x (x - 1)
4x²+8x-10=0
a = 4
b = 8
c = -10