B D C 4. ABC is an isosceles triangle with AB = AC and AD is one of its altitudes
(1) State the three pairs of equal parts in AADB and AADC.
(ii) Is AADB = AADC? Why or why not?
(iii) Is ZB=ZC? Why or why not?
(iv) Is BD=CD? Why or why not?
(1) State the three pairs of equal parts in AADB and AADC.
(ii) Is AADB = AADC? Why or why not?
(iii) Is ZB=ZC? Why or why not?
(iv) Is BD=CD? Why or why not?
Answers & Comments
Answer:
Given in \bigtriangleup AD\! B and \bigtriangleup ADC.
AB= AC
\angle ADB = \angle ADC=90^0
AD = AD ( Common side)
ii) So, by RHS Rule of congruency, we conclude
\bigtriangleup ADB\cong \bigtriangleup ADC
iii) Since both triangles are congruent all the corresponding parts will be equal.
So,
\angle B= \angle C
iv) Since both triangles are congruent all the corresponding parts will be equal.
So,
BD= CD.