- by = a^2 + b^2 [Equation 1]
x + y= 2a [Equation 2]
Multiply Equation 2 by b
=> bx + by= 2 ab [Equation 3]
Add Equation 1 and 3
⇒ ax + bx - by + by = a^2 + b^2 + 2ab
⇒ (a + b)x = a^2 + b^2 + 2ab = (a + b)^2 [Using Identity we get]
$$\bf\huge{\implies x = \dfrac{(a+b)^2}{a+b} = a + b}$$
Put value x in Equation (2)
(a + b) + y = 2a
y = 2a - (a + b)
y = 2a - a - b
y = a - b
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Answers & Comments
- by = a^2 + b^2 [Equation 1]
x + y= 2a [Equation 2]
Multiply Equation 2 by b
=> bx + by= 2 ab [Equation 3]
Add Equation 1 and 3
⇒ ax + bx - by + by = a^2 + b^2 + 2ab
⇒ (a + b)x = a^2 + b^2 + 2ab = (a + b)^2 [Using Identity we get]
$$\bf\huge{\implies x = \dfrac{(a+b)^2}{a+b} = a + b}$$
Put value x in Equation (2)
(a + b) + y = 2a
y = 2a - (a + b)
y = 2a - a - b
y = a - b