AVOGADRO'S LAW If 0.25 mol of Argon gas occupies a volume of 7.62 mL at a particular temperature and pressure, what volume would 0.43 mol of Argon have under the same conditions?
Avogadro's Law states that equal volumes of gases at the same temperature and pressure contain equal numbers of molecules. Therefore, we can use the law to solve the problem.
Formula:
V1/n1 = V2/n2
where V1 and n1 are the initial volume and number of moles, and V2 and n2 are the final volume and number of moles.
Given:
n1 = 0.25 mol
V1 = 7.62 mL
n2 = 0.43 mol
We need to find V2.
Using the formula:
V1/n1 = V2/n2
V2 = (V1/n1) * n2
V2 = (7.62 mL/0.25 mol) * 0.43 mol
V2 = 13.06 mL
Therefore, 0.43 mol of Argon gas would occupy a volume of 13.06 mL under the same conditions.
Answers & Comments
Answer:
Avogadro's Law states that equal volumes of gases at the same temperature and pressure contain equal numbers of molecules. Therefore, we can use the law to solve the problem.
Formula:
V1/n1 = V2/n2
where V1 and n1 are the initial volume and number of moles, and V2 and n2 are the final volume and number of moles.
Given:
n1 = 0.25 mol
V1 = 7.62 mL
n2 = 0.43 mol
We need to find V2.
Using the formula:
V1/n1 = V2/n2
V2 = (V1/n1) * n2
V2 = (7.62 mL/0.25 mol) * 0.43 mol
V2 = 13.06 mL
Therefore, 0.43 mol of Argon gas would occupy a volume of 13.06 mL under the same conditions.
Verified answer
V2=V1•n2/n1
V2=7.62mL• 0.25 mol of Ar / 0.43 mol of Ar
V2=3.2766ml/0.43
V2= 13.11ml