Assume that a person takes 0.100 g antacid. How many mol of MgCl2 will be produced from the ingested antacid, assuming all of the antacid undergoes the reaction?
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Answer:
Mg(OH)2 is the antacid; m(Mg(OH)2) = 0.100 g;
Molar mass Mr(Mg(OH)2) = Ar(Mg) + 2Ar(O) + 2Ar(H) = 24.305 g/mol + 2*16 g/mol + 2*1 g/mol = 58.305 g/mol.
n(Mg(OH)2) = m(Mg(OH)2)/Mr(Mg(OH)2) = (0.100 g)/(58.305 g/mol) = 0.0017 mol;
n(MgCl2) = n(Mg(OH)2) (stoichiometric coefficients);
n(MgCl2) = 0.00172 mol.