Answer:
translate english to
Explanation:
Therefore, according to first case, we have
x−10=y+10
x=y+20 ....(1)
By second case, we have
x+20=2(y−20)
x=2y−60 ....(2)
Solving (1) and (2), we get
y+20=2y−60
⇒y=80
Putting y=80 in equation (1), we get
x=80+20=100
So, the number of students in hall A=100 and the number of students in hall B=80
..............Therefore, according to first case, we have
x−10=y+1010=y+10
..............
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Answers & Comments
Answer:
translate english to
Explanation:
Therefore, according to first case, we have
x−10=y+10
x=y+20 ....(1)
By second case, we have
x+20=2(y−20)
x=2y−60 ....(2)
Solving (1) and (2), we get
y+20=2y−60
⇒y=80
Putting y=80 in equation (1), we get
x=80+20=100
So, the number of students in hall A=100 and the number of students in hall B=80
..............Therefore, according to first case, we have
x−10=y+1010=y+10
x=y+20 ....(1)
By second case, we have
x+20=2(y−20)
x=2y−60 ....(2)
Solving (1) and (2), we get
y+20=2y−60
⇒y=80
Putting y=80 in equation (1), we get
x=80+20=100
So, the number of students in hall A=100 and the number of students in hall B=80
..............