Step-by-step explanation:

Find the cost price of one watch at gain of 10% :

C.P (S.P x 100)/(100 + gain)

= (2970 × 100)/(100 + 10)

31

297000/110 =

= 2700

Find the cost price of other watch at loss of 10% :

C.P (S.P x 100)/(100 - loss)

= (2970 × 100)/(100 - 10)

=

= 297000/90

= 3300

Now,

We have,

Selling price of two watch = Rs (2970 + 2970) = Rs 5940 Cost price of two watch = Rs (2700 + 3300) = Rs 6000

Cost Price> Selling price

Loss C.P - S.P

Rs (6000 - 5940)

= Rs 60

Loss %= (loss x 100)/ C.P

In the first case, if cost price is Rs. 100 then sale price is 100 - 10 = Rs. 90 and in second case if cost price is Rs. 100, then, Sale price is 100 + 10= Rs. 110Actual cost price : For first case = 300 × 100 / 90 = 1000 / 3 = Rs. 333.33. For second case actual cost price = 300 ×100 / 110 = 3000/11 = Rs. 272.73.Hence, total cost price = 333.33 + 272.73 = Rs. 606.06. We know that total sale price = 300 + 300 = Rs. 600So, there is a loss of 606.06 - 600 = Rs. 6.06% loss = 6.06 ×100 / 606.06 (cost price) = 1 % Ans

Learn More:-

We need to use the Cost percentage formula to solve such problems and by using the formula we can get the required answer.

Hope this helps you!